Linear Algebra Examples

Find the Square Roots of a Complex Number 4+4i
4+4i4+4i
Step 1
Calculate the distance from (a,b) to the origin using the formula r=a2+b2.
r=42+42
Step 2
Simplify 42+42.
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Step 2.1
Raise 4 to the power of 2.
r=16+42
Step 2.2
Raise 4 to the power of 2.
r=16+16
Step 2.3
Add 16 and 16.
r=32
Step 2.4
Rewrite 32 as 422.
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Step 2.4.1
Factor 16 out of 32.
r=16(2)
Step 2.4.2
Rewrite 16 as 42.
r=422
r=422
Step 2.5
Pull terms out from under the radical.
r=42
r=42
Step 3
Calculate reference angle θ̂=arctan(|ba|).
θ̂=arctan(|44|)
Step 4
Simplify arctan(|44|).
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Step 4.1
Divide 4 by 4.
θ̂=arctan(|1|)
Step 4.2
The absolute value is the distance between a number and zero. The distance between 0 and 1 is 1.
θ̂=arctan(1)
Step 4.3
The exact value of arctan(1) is π4.
θ̂=π4
θ̂=π4
Step 5
The point is located in the first quadrant because x and y are both positive. The quadrants are labeled in counter-clockwise order, starting in the upper-right.
Quadrant 1
Step 6
(a,b) is in the first quadrant. θ=θ̂
θ=π4
Step 7
Use the formula to find the roots of the complex number.
(a+bi)1n=r1ncis(θ+2πkn), k=0,1,,n-1
Step 8
Substitute r, n, and θ into the formula.
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Step 8.1
Combine (42)12 and (π4)+2πk2.
cis(42)12((π4)+2πk)2
Step 8.2
Combine c and (42)12((π4)+2πk)2.
isc((42)12((π4)+2πk))2
Step 8.3
Combine i and c((42)12((π4)+2πk))2.
si(c((42)12((π4)+2πk)))2
Step 8.4
Combine s and i(c((42)12((π4)+2πk)))2.
s(i(c((42)12((π4)+2πk))))2
Step 8.5
Remove parentheses.
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Step 8.5.1
Remove parentheses.
s(i(c((42)12(π4+2πk))))2
Step 8.5.2
Remove parentheses.
s(i(c(42)12(π4+2πk)))2
Step 8.5.3
Remove parentheses.
s(i(c(42)12)(π4+2πk))2
Step 8.5.4
Remove parentheses.
s(ic(42)12(π4+2πk))2
Step 8.5.5
Remove parentheses.
s(ic(42)12)(π4+2πk)2
Step 8.5.6
Remove parentheses.
s(ic)(42)12(π4+2πk)2
Step 8.5.7
Remove parentheses.
sic(42)12(π4+2πk)2
sic(42)12(π4+2πk)2
sic(42)12(π4+2πk)2
Step 9
Substitute k=0 into the formula and simplify.
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Step 9.1
Apply the product rule to 42.
k=0:412212cis((π4)+2π(0)2)
Step 9.2
Rewrite 4 as 22.
k=0:(22)12212cis((π4)+2π(0)2)
Step 9.3
Apply the power rule and multiply exponents, (am)n=amn.
k=0:22(12)212cis((π4)+2π(0)2)
Step 9.4
Cancel the common factor of 2.
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Step 9.4.1
Cancel the common factor.
k=0:22(12)212cis((π4)+2π(0)2)
Step 9.4.2
Rewrite the expression.
k=0:2212cis((π4)+2π(0)2)
k=0:2212cis((π4)+2π(0)2)
Step 9.5
Evaluate the exponent.
k=0:2212cis((π4)+2π(0)2)
Step 9.6
Multiply 2π(0).
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Step 9.6.1
Multiply 0 by 2.
k=0:2212cis(π4+0π2)
Step 9.6.2
Multiply 0 by π.
k=0:2212cis(π4+02)
k=0:2212cis(π4+02)
Step 9.7
Add π4 and 0.
k=0:2212cis(π42)
Step 9.8
Multiply the numerator by the reciprocal of the denominator.
k=0:2212cis(π412)
Step 9.9
Multiply π412.
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Step 9.9.1
Multiply π4 by 12.
k=0:2212cis(π42)
Step 9.9.2
Multiply 4 by 2.
k=0:2212cis(π8)
k=0:2212cis(π8)
k=0:2212cis(π8)
Step 10
Substitute k=1 into the formula and simplify.
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Step 10.1
Apply the product rule to 42.
k=1:412212cis((π4)+2π(1)2)
Step 10.2
Rewrite 4 as 22.
k=1:(22)12212cis((π4)+2π(1)2)
Step 10.3
Apply the power rule and multiply exponents, (am)n=amn.
k=1:22(12)212cis((π4)+2π(1)2)
Step 10.4
Cancel the common factor of 2.
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Step 10.4.1
Cancel the common factor.
k=1:22(12)212cis((π4)+2π(1)2)
Step 10.4.2
Rewrite the expression.
k=1:2212cis((π4)+2π(1)2)
k=1:2212cis((π4)+2π(1)2)
Step 10.5
Evaluate the exponent.
k=1:2212cis((π4)+2π(1)2)
Step 10.6
Multiply 2 by 1.
k=1:2212cis(π4+2π2)
Step 10.7
To write 2π as a fraction with a common denominator, multiply by 44.
k=1:2212cis(π4+2π442)
Step 10.8
Combine 2π and 44.
k=1:2212cis(π4+2π442)
Step 10.9
Combine the numerators over the common denominator.
k=1:2212cis(π+2π442)
Step 10.10
Simplify the numerator.
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Step 10.10.1
Multiply 4 by 2.
k=1:2212cis(π+8π42)
Step 10.10.2
Add π and 8π.
k=1:2212cis(9π42)
k=1:2212cis(9π42)
Step 10.11
Multiply the numerator by the reciprocal of the denominator.
k=1:2212cis(9π412)
Step 10.12
Multiply 9π412.
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Step 10.12.1
Multiply 9π4 by 12.
k=1:2212cis(9π42)
Step 10.12.2
Multiply 4 by 2.
k=1:2212cis(9π8)
k=1:2212cis(9π8)
k=1:2212cis(9π8)
Step 11
List the solutions.
k=0:2212cis(π8)
k=1:2212cis(9π8)
 [x2  12  π  xdx ]